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IAEI News>Focus on the Code >CMP-6
Question
1. This inquiry seeks a clarification or description of
what actually constitutes the bundling of NM cables as
relates to derating. In general, the question relates to
NM cable in single-family residences and in accessory
structures.In a TJI floor-joist system, the 1-1/2-inch
knockouts in the web of the joists can be used for
routing the NM cable. If, for example, ten No. 12 with
ground NM cables are run through a single knockout in
the TJs (which are spaced at 16inches off center) and
are supported by the knockout in the TJ — and if the
cables are not cinched, stapled, taped or otherwise
secured together but are simply fed through the
knockouts — would this close proximity and
non-continuous contact of the NM cables require
derating? Similarly, if, for example, six No. 12
with ground NM cables are routed through holes bored in
the center of wood studs and are supported by the studs
— and if the cables are not cinched, stapled, taped or
otherwise secured together — would this close
proximity and non-continuous contact of the NM cables
require derating? In the jurisdiction where I work, the
building inspectors have differing opinions on what
actually constitutes “bundling” of NM for the
purposes of derating. Some feel that the mere proximity
or contact of the cables qualifies for derating. Others
feel that unless the cables are actually cinched tightly
for over two feet, then non-continuous contact would not
qualify for derating. Is there a standard or acceptable
distance or minimum spacing that can be applied? Rather than simply relying on a consensus among
the small group of inspectors (which may or may not be
consistent with the NEC), we would like an
opinion or perspective from a more authoritative source.
Is there a standard, guideline or criteria that can be
applied to determining if bundling actually occurs? — K.C. Answer 1. This
is a question that was brought to Panel 6 in the 1999 code cycle. The panel
agreed that most contractors pulled in cables tight, leaving no slack in the
cables. This caused the cables to be snug against each other or stacked with
no maintained spacing. Additionally, there was a problem with joist gathered
or bundled cables every 16 inches where spacing was not maintained. If there
was any spacing, it soon disappeared with gravity. The NEC does not
address non-continuous or continuous contact but requires maintained
spacing. If there was 1/8 or 1/4 in. spacing that could be maintained, we
could say it is only bundled or stacked at the joist with no derating
required. I don't know of any product that is available and approved to
guarantee that cable spacing will be maintained between joists. This is
similar to a raceway where the conductors may or may not be in continuous
contact; however, derating would be required. Section 334.80 [NEC 2002], Ampacity, allows
the 90-degree column in the ampacity table to be used for derating, and the
60-degree column for maximum ampacity. It also refers to 310.15(B)(2), Adjustment
Factor, that states where
multiconductor cables are stacked or bundled longer than 600 mm (24 in.)
without maintaining spacing, the allowable ampacity of each conductor shall
be reduced as shown in Table 310.15(B)(2)(a). Therefore, if there are ten – No. 12 NM cables
pulled through 1½ in. holes in
joists without maintained spacing, the ampacity would have to be derated
using Table 310.15(B)(2)(a). Ten MN cables would have twenty
current-carrying conductors and be required to be derated to 50 percent of
the ampacity. Table 310.16 allows 30 amps in the 90-degree column with a
derating of 50 percent, equaling fifteen amps allowed on these cables and
fifteen amps of overcurrent protection. If there were six No. 12 NM cables pulled through studs, the same would apply. There
would be twelve current-carrying conductors. Section 310.15(B)(2)(a) would
require derating 50 percent of 30, equaling fifteen amps allowable, and
fifteen amps off center. If there were only four No. 12 NM cables, there
would be eight current-carrying conductors with a derating of 70 percent of
30 amps, equaling 21 amps. Twenty-amp overcurrent protection is allowed per
240.4(D). Additional derating may be required for high
ambient temperatures in attic spaces and other high temperature areas. Please
also be aware that the holes in a 3½ in. stud could
only be 1 in., leaving 1 1/4 in. on each side of the
hole. — John Stacey, Alternate CMP-6 | Return
to top | Question
2. Twice in the last 20 years I have read a
discussion to the effect that I can use the 75°C column in
Table 310.16 without derating the wires per 240.4(D) when
hooking up motors. In other words, I can hook up motors
with 12 AWG wire using the ampacity listed of 25 amps. I can
use 14 AWG wires as 20-amp wire and number 10 at 35 amps. I
have no memory of how this was justified nor am I able to find
anything in the current Code supporting this. Can you enlighten me as to whether this was
ever allowed and, if so, is it still allowed? — K. L. R. Answer 2. Thank you for your questions. Let us examine the NEC 2002 text to answer them. Section 240.4(D), Small Conductors, limits
the ampacity of 14 AWG, 12 AWG, and 10 AWG, "unless
specifically permitted in 240.4(E) through (G), the
overcurrent protection shall not exceed 15 amperes for 14 AWG,
20 amperes for 12 AWG, and 30 amperes for 10 AWG copper; or 15
amperes for 12 AWG and 25 amperes for 10 AWG aluminum and
copper-clad aluminum after any correction factors for ambient
temperature and number of conductors have been applied." An exception to the above rule for motor
protection is (G), Overcurrent Protection for Specific
Conductor Applications. "Overcurrent protection for the
specific conductors shall be permitted to be provided as
referenced in Table 240.4(G)." 430.22 Single Motor. "(A) General. Branch-circuit
conductors that supply a single motor used in a continuous
duty application shall have an ampacity of not less than 125
percent of the motor’s full-load current rating as
determined by 430.6(A)." 430.6(A)(1) Table Values. "The values
given in Table 430.147, Table 430.148, Table 430.149, and
Table 430.150, including notes, shall be used to determine the
ampacity of conductors or ampere ratings of switches,
branch-circuit short-circuit and ground-fault protection,
instead of the actual current rating marked on the motor
nameplate. Where a motor is marked in amperes, but not
horsepower, the horsepower rating shall be assumed to be that
corresponding to the value given in Tables 430.147, 430.148,
430.149, and 430.150, interpolated if necessary." 430.52(C) Rating or Setting for individual
motor circuit. (1) In Accordance with Table 430.52. "A
protective device that has a rating or setting not exceeding
the value calculated according to the values given in Table
430.52 shall be used." Some examples that might help: Example 1. A 1-hp 115-volt,
single-phase ac motor. Table 430.148. FLA=16 amps. 16 x 125% = 20 amps. A 14 AWG
conductor can be used from Table 310.16, 75°C column to feed
this motor and protected in accordance with Table 430.52. Example 2. A 3-hp, 208-volt,
single-phase ac motor. Table 430.148. FLA = 18.7 amps. 18.7 x
125% = 23.4 amps. A 12 AWG conductor can be used from Table
310.16, 75°C column to feed this motor and protected in
accordance with Table 430.52. Example 3. A 20-hp, 460-volt, 3-phase
ac motor. Table 430.150. FLA = 27 amps. 27 x 125% = 33.75
amps. A 10 AWG conductor can be used from Table 310.16, 75°C
column to feed this motor and protected in accordance with
Table 430.52. The above information is what allows the
ampacity in the 75°C column in Table 310.16 to be used for
motor circuit conductors. The only other problem would be if the
termination temperatures were less than 75°C, then the rules
in 110.14(C)(1)(a)(3) and (4) would not apply. 110.14(C) Temperature Limitations.
"The temperature rating associated with the ampacity of a
conductor shall be selected and coordinated so as not to
exceed the lowest temperature rating of any connected
termination, conductor, or device. Conductors with temperature
ratings higher than specified for terminations shall be
permitted to be used for ampacity adjustment, correction, or
both. "(1) Equipment Provisions. The
determination of termination provisions of equipment shall be
based on 110.14(A) or (B). Unless the equipment is listed and
marked otherwise, conductor ampacities used in determining
equipment termination provisions shall be based on Table
310.16 as appropriately modified by 310.15(B)(1) through (6). "(a) Termination provisions of
equipment for circuits rated 100 amperes or less, or marked
for 14 AWG through 1 AWG conductors, shall be used only for
one of the following: "(1) Conductors rated 60°C (140°F) "(2) Conductors with higher
temperature ratings, provided the ampacity of such conductors
is determined based on the 60°C (140°F) ampacity of the
conductor size used "(3) Conductors with higher
temperature ratings if the equipment is listed and identified
for use with such conductors "(4) For motors marked with design
letters B, C, D, or E, conductors having an insulation rating
of 75°C (167°F) or higher shall be permitted to be used
provided the ampacity of such conductors does not exceed the
75°C (167°F) ampacity." 240.4(D) Small Conductors. "Unless
specifically permitted in 240.4(E) through (G), the
overcurrent protection shall not exceed 15 amperes for 14 AWG,
20 amperes for 12 AWG, and 30 amperes for 10 AWG copper; or 15
amperes for 12 AWG and 25 amperes for 10 AWG aluminum and
copper-clad aluminum after any correction factors for ambient
temperature and number of conductors have been applied." The same rules would apply to conductors
supplying ac equipment and the protective device sized from
440.22(A). — O. P. Post, CMP-6 | Return
to top | Question
3. In NEC Table 310.16, information is
listed for derating conductors due to ambient temperatures.
The ampacities listed with the table are based on an ambient
temperature of 30°C. Are conductors that are installed where
outdoor ambient temperatures can reach the 41–45°C range in
the summer months required to be derated using these tables? — B.B. Answer 3. The answer to this question is, yes, the correction
factors would apply. The ampacity of conductors in Table
310.16 is based on an ambient temperature of 30°C (86°F). If
these conductors are installed in a higher temperature, in
your example 41–45°C, then they must be derated using the
correction factors at the bottom of the table. The 90°C
column can be used for this calculation if conductors with
90°C insulation are used, which is .87. After the ampacity is
calculated, the conductor must be taken from the 75°C column.
An example would be 500 kcmil in the 90°C column is 430 amps
at 30°C; after derating by .87 for 41–45°C it would be 374
amps, which would still be good for a 400-amp feeder or
service conductor. — O.P. Post, CMP-6 | Return
to top | Question
4. My question is concerning derating of conductor
in accordance with Section 310.15, Table 310.15(b)(2)(a). It
has always been my belief that you could use the 90°C chart
of 310.16 when derating a conductor. However, one of the local
inspectors states that you must derate using the 60° or 75°C
chart, depending on the rating of the termination point of the
conductors. Please help clear this up for me. — T. C. Answer 4. Thank
you for giving me an opportunity to talk about a frequently
misunderstood subject. I always have questions about this
topic in my code class. Take a closer look at NEC 110.14(C).
"The temperature rating associated with the ampacity of a
conductor shall be selected and coordinated so as not to exceed
the lowest temperature rating of any connected termination,
conductor, or device. Conductors with temperature ratings higher
than specified for terminations shall be permitted to be used for
ampacity adjustment, correction, or both." This means that
the derating for adjustment (the number of conductors in a raceway
or cable) or correction (ambient temperature other than 30°C
(86°F) or both can start with the allowable ampacity for the type
of conductor being used. Let’s try different scenarios. If we are
installing two 50-amp, 240-volt circuits in one raceway, what size
conductors are required? The receptacle and the breaker are rated
for 60°C termination. In Table 310.15(b)(2)(a), Adjustment
Factors, there are two columns. The first column is entitled
"Number of Current-Carrying Conductors." The second
column is titled "Percent of Values in Tables 310.16 through
310.19 as Adjusted for Ambient Temperature if Necessary."
There are four current-carrying conductors and one equipment
ground. The equipment ground is not counted. The table requires a
reduction to 80 percent of the conductor ampacity due to more than
three current-carrying conductors in a raceway. If we were using
90°C conductors, we would start the derating in the 90°C column.
If we were using 60° or 75°C conductors, we would start the
derating in the 60°C or 75°C column accordingly. Let’s try a 6 AWG 90°C conductor. In Table
310.16, the allowable ampacity is 75 amps x .80 adjustment factor
= 60 amps allowable on this conductor. Remember, 110.14(C) would
limit the ampacity to the 60°C column due to the devices being
rated 60 amps. Therefore, 55 amperes in the 60°C column could not
be exceeded for the load. A 50-amp circuit would not exceed, and a
6 AWG, 90°C conductor would work. Now try a 6 AWG 75°C conductor that has an
allowable ampacity of 65 amps x .80 adjustment factor = 52 amps
available. A 50-amp circuit would not exceed 52 amps allowing a 6
AWG, 75°C conductor to be used. To install a 50-amp circuit through an attic
where the conductors are exposed to high ambient temperatures
around 130°C we look at the bottom of Table 310.16, which is a
Correction Factor Table for temperatures other than 30°C (86°F).
There is a correction factor of .76 for 6 AWG under the 90°C
column. The reason it is under the 90°C column is to allow
derating from that column. A 6 AWG 90°C conductor has an
allowable ampacity of 75 amperes x .76 correction factor. This
will only allow 57 amps on the 90°C conductor. Remember 110.14(C)
would limit the ampacity to the 60°C column due to the devices
being rated 60 amps. Therefore 55 amperes could not be exceeded.
After derating the conductor to 57 amps allowable, a 50-amp
circuit would be allowed on 6 AWG. We are installing a 50-amp circuit. The breaker
and the outlet are rated at 75°C. What size conductors are
required? Table 310.16 allows 55 amps on an 8 AWG in the 90°C
column; however, 110.14(C) limits the ampacity due to the
temperature rating of the device. Since the device—both the
breaker and the outlet—is only rated for 75°C, Section
110.14(C) would limit the ampacity to the 75°C column of 310.16
due to the temperature rating of the device. An 8 AWG is 50
amperes in the 75°C column. Therefore, an 8 AWG would comply. —
John Stacey, CMP-6 | Return
to top | Question
5. I have attached some photographs of NM cable
installation in factory-built housing (see photos
1 through 6). In your opinion, does the installation pictured
represent bundling (NEC 310.15), therefore requiring
ampacity derating? — G. N. Answer 5. The
pictures are not real clear, but it looks like there are at least
five two-wire cables and two three-wire cables in the bundle. In
the two-wire cable, both wires are current-carrying. The
three-wire cable, depending on what it serves, could be two or
three current-carrying conductors. The cables are bundled and
require derating, according to NEC 310.15(B)(2). If all of
the cables are NM-B, you can use the 90-degree column for the
ampacity adjustment, there are 14 to 16 current-carrying
conductors in this bundle. Table 310.15(B)(2)(a) requires a 50 percent
adjustment for 10–20 current-carrying conductors. Using Table
310.16, the 10 AWG conductors must be on a 20-amp overcurrent
device, the 12 AWG conductors must be on a 15-amp overcurrent
device, and the 14 AWG conductors can be on a 15-amp overcurrent
device. 10 AWG is 40 amps x 50%= 20 amps 12 AWG is 30 amps x 50% = 15 amps 14 AWG is 25 amps x 50% = 12.5 amps rounded up
to the next standard overcurrent device = 15 amps. — O. P. Post, CMP-6 | Return
to top | Question
6. We are writing to request clarification of Section
310-15(b)(6) [1999 NEC]. We are electrical contractors
doing service work in 34 different jurisdictions on the central
coast of California. The inspectors in one local jurisdiction have
taken this section (per the clarification on page 153 of the IAEI Analysis
of the 1999 National Electrical Code) to apply only to the
main power feeders (between the main disconnect and the
branch-circuit panel board) and not to the service-entrance
conductors. We take the section to mean that for single-phase,
120/240-volt, 3-wire residential service, the service-entrance
conductors, as well as the service-lateral conductors, as well as
the feeder conductors can all be sized according to Table
310-15(b)(6). By our interpretation, when we install or
replace a typical 100-A, single-phase residential service, we will
use 4 AWG copper service-entrance conductors. These local
inspectors would have us use 3 AWG (which is not generally
available, so we have to use 2 AWG). Which interpretation is
correct? — V. K. Answer 6. Section
310-15(b)(6) in NEC- 1999 was previously the text in note 3
to the ampacity tables of 0 to 2000 volts. If a single set of
3-wire, single-phase, service-entrance conductors in a raceway or
cable supplies a one-family, two-family, or multifamily dwelling,
the reduced conductor size permitted by Section 310-15(b)(6) is
applicable to the service-entrance conductors, service-lateral
conductors, or any feeder conductors that supply the main power
feeder to a dwelling unit. This section permits the main power
feeder to a dwelling unit to be sized based on the conductor sizes
in table 310-15(b)(6) even if other loads, such as air
conditioning units and swimming pools, are fed from the same. The
feeder conductors to a dwelling are not required to be larger than
its service-entrance conductors. An example of this would be if
you installed the service panel outside and from that location fed
an air-conditioning unit, then ran a feeder into the dwelling unit
to a subpanel, that feeder would be sized from table 310-15(b)(6),
the 4 AWG copper would be 100 amps, and 2 AWG aluminum would also
be 100 amps.— O. P. Post, CMP-6 | Return
to top | The views of the authors of Focus on
the Code and the editor are provided solely as a public service. |
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